JEE PHYSICS MCQ: GRAVITATION

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Application +4 | -1

Two isolated point masses

{m}

and

{M}

are separated by a distance

\ell

. The moment of inertia of the system about an axis passing through a point where gravitational field is zero and perpendicular to the line joining the two masses, is

View answer and explanation

Correct option: A

\frac{m^2+M^2}{(\sqrt{m}+\sqrt{M})^2}\ell^2

Option A (

\frac{m^2+M^2}{(\sqrt{m}+\sqrt{M})^2}\ell^2

) is correct because it represents the moment of inertia calculated about the point where the gravitational field is zero, considering the distances of both masses from that point.

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11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

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v_e

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