NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Analyzing +4 | -1

The complex with highest magnitude of crystal field splitting energy

\left(\Delta_{0}\right)

View answer and explanation

Correct option: B

\left[\mathrm{Cr}\left(\mathrm{OH}_{2}\right)_{6}\right]^{3+}

Option B (

\left[\mathrm{Cr}\left(\mathrm{OH}_{2}\right)_{6}\right]^{3+}

) is correct because

Cr^{3+}

has a

d^3

configuration, leading to a larger crystal field splitting compared to other options with weaker ligand field stabilization.

More Questions from CO-ORDINATION COMPOUNDS

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\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

\text{ox =}

x

{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]