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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy
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Application +4 | -1
∫(1−x)23xdx=\int(1-x)^{23} x d x=
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Correct option: C
(1−x)2525−(1−x)2424+c\frac{(1-x)^{25}}{25}-\frac{(1-x)^{24}}{24}+c
Option C is correct because it results from substituting t=1−xt = 1-x and integrating the resulting polynomial.

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