$\smallint \,\,\frac{{dx}}{{x + \sqrt x }}$ is equal to

$\frac{1}{2}\,\,\log \,\,\left( {1 + \sqrt x \,} \right) + c$

$\frac{1}{4}\,\,\log \,\,\left( {1 + \sqrt x \,} \right) + c$

$3\,\,\log \,\,\left( {1 + \sqrt x \,} \right) + c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\,\frac{{dx}}{{x + \sqrt x }}

is equal to

View answer and explanation

Correct option: B

2\,\,\log \,\,\left( {1 + \sqrt x \,} \right)\, + c

Option B (

2\,\log \,\left( {1 + \sqrt x \} \right)\, + c

) is correct because after substitution, the integral simplifies and evaluates to this expression.