JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\frac{\pi }{2} < \theta < \pi

, then

\sqrt {\frac{{1 - \sin \,\,\theta }}{{1 + \sin \,\,\theta }}} + \sqrt {\frac{{1 + \sin \,\,\theta }}{{1 - \sin \,\,\theta }}}

is equal to

View answer and explanation

Correct option: B

- \,2\,\,\sec \,\,\theta

Option B (

\ - \,2\sec \theta

) is correct because the expression simplifies to

-2\sec \theta

when

\frac{\pi}{2} < \theta < \pi

, considering the sign of

\cos \theta

in the second quadrant.

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\triangle A B C

C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=