JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

The domain of the function

f\left( {x\;} \right) = {\log _{2x - 1}}\left( {x - 1} \right)

View answer and explanation

Correct option: A

\left( {1,\;\infty } \right)

Option D (None of these) is incorrect. Option A

\left( {1,\;\infty } \right)

is correct because the argument of the logarithm and the base must be positive and the base cannot be 1.

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f\left( x \right) = x - \left[ x \right]

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f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}