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JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1

Assertion (A) :

{Cl}_2

or

{Br}_2

changes

{KI}

into

{I}_2

(violet in

{CCl}_4

layer),

{Cl}_2

changes

{KBr}

into

{Br}_2

(orange-yellow in

{CCl}_4

layer). Thus,

{Cl}_2

would change mixture of

{KI}

and

{KBr}

into violet layer in

{CCl}_4

.

Reason (R) : Oxidising power is in order

{I}_2 < {Br}_2 < {Cl}_2 < {F}_2

.

View answer and explanation

Correct option: A

Both

\mathbf{A}

and

\mathbf{R}

are true and

\mathbf{R}

is the correct explanation of

\mathbf{A}

.

Option A (Both A and R are true and R is the correct explanation of A) is correct because chlorine is a stronger oxidizing agent than bromine, which is stronger than iodine, thus chlorine will oxidize both iodide and bromide to their respective halogens.

More Questions from P-BLOCK ELEMENTS

Practice All Chapter MCQs →

The gas used for inflating the tyres of aeroplanes is: Which of the following is correct stability order of oxides of

17^{\text {th }}

group elements is: Assertion: Ozone is a powerful oxidising agent in comparison to

{O}_2

.

Reason: Ozone is diamagnetic but

{O}_2

is paramagnetic. Which of the following is kept in water?

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

are isoelectronic but in contrast to

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

is chemically inert because of: Consider the following statements

(i) Reaction

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

shows reducing character of sulphur dioxide

(ii)

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

gas can be dried effectively by using conc.

{H}_2 {SO}_4

.

(iv) One of the major use of

{H}_2 {SO}_4

is in the manufacture of fertilizers.

Which of the following is the correct code for the statements above?