If the molar conductance value of ${\rm{C}}{{\rm{a}}^{2 + }}$ and ${\rm{C}}{{\rm{l}}^ - }$ at infinite dilution are respectively $ 118.88 \times {10^{ - 4}}{{\rm{m}}^2}{\rm{mho}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$ and $ 77.33 \times {10^{ - 4}}{{\rm{m}}^2}{\rm{mho}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$ then that of $CaC{l_2}$ is (in $ {{\rm{m}}^2}{\rm{mho}}{\kern 1pt} {\kern 1pt} {\kern 1pt} {\rm{mo}}{{\rm{l}}^{ - 1}}$)

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Hard

1 of 1

Application +4 | -1

If the molar conductance value of

\mathrm{C}{\mathrm{a}^{2 + }}

and

\mathrm{C}{\mathrm{l}^ - }

at infinite dilution are respectively

118.88 \times {10^{ - 4}}{\mathrm{m}^2}\mathrm{mho}{\kern 1pt} {\kern 1pt} {\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

and

77.33 \times {10^{ - 4}}{\mathrm{m}^2}\mathrm{mho}{\kern 1pt} {\kern 1pt} {\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

then that of

CaC{l_2}

is (in

{\mathrm{m}^2}\mathrm{mho}{\kern 1pt} {\kern 1pt} {\kern 1pt} \mathrm{mo}{\mathrm{l}^{ - 1}}

)

View answer and explanation

Correct option: C

273.54

\times {10^{ - 4}}

Option C (273.54

\times {10^{ - 4}}

) is correct because it is calculated by adding the molar conductance of Ca2+ and twice the molar conductance of Cl-.