JEE PHYSICS MCQ: SEMI CONDUCTOR DEVICES

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In a common-base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor (

\mathrm{\beta }

) will be

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Correct option: A

Option A (49) is correct because the base current amplification factor is calculated using the formula

\beta = \frac{{I_C}}{{I_B}}

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A PN-junction has a thickness of the order of In a

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transistor the base is the

N

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P

-region is A solid reflects incident light and its electrical conductivity decreases with temperature. The binding in this solid is An alternating current can be converted into direct current by a A N–P–N transistor is used in inverse active mode of operation then its emitter base junction should be in In the case of constants

\mathrm{\alpha\; and\; \beta }

of a transistor