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JEE PHYSICS MCQ: OSCILLATIONS

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Two particles are executing S.H.M. The equations of their motion are

y_1=10 \sin \left(\omega t+\frac{\pi T}{4}\right), y_2=25 \sin \left(\omega t+\frac{\sqrt{3} \pi T}{4}\right)

.
What is the ratio of their amplitude?

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Correct option: B

0.086805556

The correct answer is B (02:05) because the ratio of amplitudes is simply the ratio of the coefficients of the sine functions.

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