JEE MATHEMATICS MCQ: CIRCLES

1 Easy

1 of 1

Analyzing +4 | -1

Let

P Q

and

R S

be tangents at the extremities of diameter

P R

of a circle of radius

r

. If

P S

and

R Q

intersect at a point

X

on the circumference of the circle, then

2 r

equals

View answer and explanation

Correct option: A

\sqrt{P Q \cdot R S}

Option A (

\sqrt{P Q \cdot R S}

) is correct because using similar triangles formed by the intersecting tangents and the diameter, we can show that

2r = \sqrt{PQ \cdot RS}

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x

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\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

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x^2+y^2=1

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(-1,0)

A P, A Q

A R

G P

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\cos \gamma / 2

x+y=6

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x+y=5

x-y=1

9 \pi