JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

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The negation of

x \in \mathrm{A} \cap \mathrm{B} \Rightarrow(x \in \mathrm{A}

and

x \in \mathrm{B})

is ......

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Correct option: C

x \in \mathrm{A} \cap \mathrm{B}

and

(x \notin \mathrm{A}

x \notin \mathrm{B})

Option C is the correct answer because it accurately represents the negation of the biconditional statement using the correct logical operators.

More Questions from MATHEMATICAL REASONING

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p:A

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\sqrt{3}

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{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

p

n

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n

p \Leftrightarrow q