JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int \frac{x \sin ^{-1} x}{\sqrt{1-x^2}} d x=

View answer and explanation

Correct option: A

x-\sqrt{1-x^2} \sin ^{-1} x+c

Option A (

x-\sqrt{1-x^2} \sin ^{-1} x+c

) is correct because substituting

\sin^{-1}x = t

simplifies the integral, and integration by parts yields the correct result.

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