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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫(sin⁡x)−11/3(cos⁡x)−1/3dx=−3(1+4tan⁡2x)8H(x)+c\int(\sin x)^{-11 / 3}(\cos x)^{-1 / 3} d x=-\frac{3\left(1+4 \tan ^2 x\right)}{8 H(x)}+c, where H(x)H(x) is
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Correct option: D
(tan⁡x)8/3⁡(\tan x)^{\operatorname{8/3}}
Option D ((tan⁡x)8/3\tan x)^{8/3}) is correct because by rewriting the integral in terms of tan⁡x\tan x and then substituting, we can find the expression for H(x).

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