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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy
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Application +4 | -1
If x+iy=a+ibc+idx + iy = \sqrt {\frac{{a + ib}}{{c + id}}}, then x2+y2{x^2} + {y^2} is equal to
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Correct option: D
None of these
None of these is the correct answer. The correct answer is a2+b2c2+d2\sqrt{\frac{{{a^2} + {b^2}}}{{{c^2} + {d^2}}}} because by taking the modulus squared of both sides of the equation, we can find x2+y2{x^2} + {y^2}.

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