JEE PHYSICS MCQ: GRAVITATION

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A satellite of mass 200 kg is orbiting around the earth at a height of 400 km above its surface. The energy required to send it out of the earth’s gravitational influence is (Mass of earth

= 6 \times {10^{24}}kg

, Radius of earth = 6000 km,

G = 6.67 \times {10^{ - 11}}\,N{m^2}\,k{g^{ - 2}}

)

View answer and explanation

Correct option: C

4 \times {10^9}J

Option C (

4 \times {10^9}J

) is correct because it is the energy required to escape Earth's gravitational influence, calculated using the gravitational potential energy formula.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

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