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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Analyzing +4 | -1
Consider the following reaction:
C6H6(l)+152O2(g)→6CO2(g)+3H2O(g){C_6}{H_6}\left( l \right) + \frac{{15}}{2}{O_2}\left( g \right) \to 6C{O_2}\left( g \right) + 3{H_2}O\left( g \right)
Sign of ΔH,   ΔG   &   ΔS\Delta H,\,\,\,\Delta G\,\,\,\& \,\,\,\Delta S for the above reaction will be
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Correct option: B
−,  −,  +- ,\,\, - ,\,\, +
Option B ( - , - , + ) is correct because combustion reactions are exothermic (negative Δ H), spontaneous (negative Δ G), and increase disorder (positive Δ S).

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