$\smallint \,\,\sqrt x e\,{\,^{\sqrt x }}dx$ is equal to

$2\,\sqrt x - {e^{\sqrt x }} - \,\,4\,\sqrt {x{e^{\sqrt x }}} + \,\,c$

$\left( {1\,\, - \,\,4\,\,\sqrt x } \right){e^{\sqrt x }} + \,\,c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \,\,\sqrt x e\,{\,^{\sqrt x }}dx

is equal to

View answer and explanation

Correct option: B

\left( {2x\,\, - \,\,4\,\sqrt x + 4} \right){e^{\sqrt x }} + \,\,c

Option B (

\left( {2x\, - \,4\,\sqrt x + 4} \right){e^{\sqrt x }} + \,c

) is correct because it is the result of integrating the given expression using substitution and integration by parts.