Skip to main content
Back to FUNCTIONS

JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium
1 of 1
Analyzing +4 | -1
If f(x+y)=f(x)f(y)∀x,y∈Rf(x+y)=f(x) f(y) \forall x, y \in R and f(0)≠0f(0) \neq 0, then the function ϕ(x)=f(x)1+(f(x))2+sin⁡(π[x2+x]1+sin⁡(cos⁡x)\phi(x)=\frac{f(x)}{1+(f(x))^2}+\frac{\sin \left(\pi\left[x^2+x\right]\right.}{1+\sin (\cos x)} (where [] denote the greatest integer function) is
View answer and explanation
Correct option: A
An even function
Option A (An even function) is correct because the function φ(x) is shown to satisfy φ(-x) = φ(x), indicating it is an even function.

More Questions from FUNCTIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.