JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Understanding +4 | -1

The domain of the real function

f\left( x \right) = \frac{1}{{\sqrt {4 - {x^2}} }}

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Correct option: C

(-2, 2)

Option C ((-2, 2)) is correct because the expression inside the square root must be positive, leading to the inequality 4 - x² > 0.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f^{-1}(x)

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f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}