JEE PHYSICS MCQ: THERMODYNAMICS

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The temperature of the source of a Carnot's heat engine is

1000^{\circ} \mathrm{C}

. Its efficiency could be

100 \%

only if the temperature of the sink is

View answer and explanation

Correct option: D

-273.16^{\circ} \mathrm{C}

The correct answer is D (-273.16°C) because for a Carnot engine to have 100% efficiency, the sink temperature must be absolute zero (0 K), which is -273.16°C.

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The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand

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at constant pressure

{10^3}N/{m^2},

the work done is A thermodynamic process in which temperature

T

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P

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V

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\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)