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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫log⁡(x+1+x2)1+x2dx=\int \frac{\log \left(x+\sqrt{1+x^2}\right)}{\sqrt{1+x^2}} d x=
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Correct option: A
12[log⁡(x+1+x2)]2+c\frac{1}{2}\left[\log \left(x+\sqrt{1+x^2}\right)\right]^2+c
Option A (12[log⁡(x+1+x2)]2+c\frac{1}{2}\left[\log \left(x+\sqrt{1+x^2}\right)\right]^2+c) is correct because it is the result of the integration after using a suitable substitution.

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