JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

f: \mathrm{A} \rightarrow \mathrm{B}

be a function defined as

f(x)=\frac{x-1}{x-2}

, where

A=R-\{2\}

and

B=R-\{1\}

. Then

f

View answer and explanation

Correct option: D

invertible and

f^{-1}(y)=\frac{2 y-1}{y-1}

The function is invertible, and its inverse is found by swapping x and y and solving for y, resulting in option D (

f^{-1}(y)=\frac{2 y-1}{y-1}

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}