JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\cos \theta+\sin \phi=m

and

\sin \theta+\cos \phi=n

, then

\frac{1}{2}\left(m^2+n^2-2\right)

is equal to

View answer and explanation

Correct option: B

\sin (\theta+\phi)

Option B (

\sin (\theta+\phi)

) is correct because simplifying the expression

\frac{{1}}{{2}}(m^2 + n^2 - 2)

using the given equations results in

\sin (\theta + \phi)

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