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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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Application +4 | -1
Two containers A and B are such that,VA=0.10 m3,PA=1.40MPa,VB=0.15 m3,PB=0.7MPaV_A=0.10 \mathrm{~m}^3, P_A=1.40 \mathrm{MPa}, V_B=0.15 \mathrm{~m}^3, P_B=0.7 \mathrm{MPa}

After opening the tap, final pressure in the containers is (Assume temperature of A and B are same)
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Correct option: B
0.98 MPa0.98 \mathrm{~MPa}
Option B (0.98 MPa0.98 \mathrm{~MPa}) is correct because it is calculated using the conservation of moles and the ideal gas law, considering the combined volume.

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