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JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1
What will be the A{A} and B{B} in the following equations.

8NH3+3Cl2(A)→6NH4Cl+N2NH3+3Cl2(B)→NCl3+3HCl\begin{gathered} 8{{N}}{{{H}}_3} + \mathop {3{{C}}{{{l}}_2}}\limits_{(A)} \to 6{{N}}{{\text{H}}_4}{{Cl}} + {{{N}}_2} \quad \\ {{N}}{{{H}}_3} + \mathop {3{{C}}{{{l}}_2}}\limits_{(B)} \to {{NC}}{{{l}}_3} + 3{{HCl}} \quad \\ \end{gathered}
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Correct option: A
A={A}= Excess, B={B}= Excess
Option B (N2O5\mathrm{N}_2 \mathrm{O}_5) is correct because when N₂O₅ is hydrolyzed, it forms only HNO₃, where nitrogen remains in the +5 oxidation state, thus no disproportionation occurs.

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