Skip to main content
Back to INDEFINITE INTEGRATION

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Hard
1 of 1
Analyzing +4 | -1
Let I(x)=∫x2(xsec⁡2+tan⁡x)(xtan⁡x+1)2dxI(x)=\int \frac{x^{2}\left(x \sec ^{2}+\tan x\right)}{(x \tan x+1)^{2}} d x. If I(0)=0I(0)=0, then I(π4)I\left(\frac{\pi}{4}\right) is equal to
View answer and explanation
Correct option: C
log⁡e(π+4)232−π24(π+4)\log _{e} \frac{(\pi+4)^{2}}{32}-\frac{\pi^{2}}{4(\pi+4)}
Option C (log⁡e(π+4)232−π24(π+4)\log _{e} \frac{(\pi+4)^{2}}{32}-\frac{\pi^{2}}{4(\pi+4)}) is correct because it is the result of evaluating the definite integral with the given initial condition.

More Questions from INDEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.