JEE PHYSICS MCQ: OSCILLATIONS

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A second's pendulum clock has a steel wire. The clock shows correct time at

25^{\circ} \mathrm{C}

. How much time does the clock loss or gain, in one week, when the temperature in increased to

35^{\circ} \mathrm{C}

\left(\alpha_{\text {steel }}=1.2 \times 10^{-5} /{ }^{\circ} \mathrm{C}\right)

View answer and explanation

Correct option: D

36.28 \mathrm{~s}

Option D (

36.28 \mathrm{~s}

) is correct because it calculates the time lost by the pendulum clock due to the increase in temperature, considering the linear expansion of the steel wire.

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