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JEE MATHEMATICS MCQ: RELATIONS

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Let AA be the set of first ten natural numbers and let RR be a relation on AA defined by (x,y)∈R⇔x+2y=10(x, y) \in R \Leftrightarrow x+2 y=10 i.e., R={(x,y):x∈A,y∈AR=\{(x, y): x \in A, y \in A and x+2y=10}x+2 y=10\}. Then domains of R−1R^{-1}
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Correct option: B
{4,3,2,1}\{4,3,2,1\}
Option B ({4,3,2,1}\{4,3,2,1\}) is correct because it represents the domain of the inverse relation, which is the range of the original relation.

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