${\rm{NC}}{{\rm{l}}_3}$ on hydrolysis yields:

${\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{\;and}}\,{\rm{ HOCl}}$

${{\rm{N}}_{\rm{2}}}{\mkern 1mu} {\mkern 1mu} \,{\rm{and}}\,\,{\rm{NOCl}}$

${{\rm{N}}_2}{\rm{O}}\,\,\,{\rm{and}}\,\,{\rm{N}}{{\rm{H}}_{\rm{3}}}{\rm{\;}}\;$

JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

1 Easy

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Understanding +4 | -1

\mathrm{NC}{\mathrm{l}_3}

on hydrolysis yields:

View answer and explanation

Correct option: C

\mathrm{N}{\mathrm{H}_\mathrm{3}}\mathrm{\;and}\,\mathrm{ HOCl}

Option C (

\mathrm{N}{\mathrm{H}_\mathrm{3}}\mathrm{\;and}\,\mathrm{ HOCl}

) is correct because the hydrolysis of NCl3 results in the formation of ammonia and hypochlorous acid.

Practice All Chapter MCQs →

17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4