JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\cos (\theta-\alpha)=a

and

\sin (\theta-\beta)=b

, then

\cos ^2(\alpha-\beta)+2 a b \sin (\alpha-\beta)

is equal to

View answer and explanation

Correct option: C

a^2+b^2

The correct answer is

a^2+b^2

because the expression simplifies to

a^2 + b^2

using trigonometric identities and the given substitutions.

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