JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

0 \leq a \leq 3,0 \leq b \leq 3

and the equation

x^2+4+3 \cos (a x+b)=2 x

has atleast one solution, then the value of

a+b

View answer and explanation

Correct option: C

\pi

Option C (

\pi

) is correct because the equation has at least one solution only if

\cos(ax+b) = -1

when

x=1

, leading to

a+b = \pi

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\mathrm{X}

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