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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1
A drop of liquid of diameter 2.8 mm breaks up into 125 identical drops. The change in energy is nearly (S=75  dyne  cm−1)\left( {S = 75\,\,\mathrm{dyne}\,\,\mathrm{c}{\mathrm{m}^{ - 1}}} \right)
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Correct option: D
74 erg
Option D (74 erg) is correct because the change in energy is calculated by multiplying the surface tension by the increase in surface area after the drop breaks into smaller droplets.

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