The value of $\smallint \frac{{d\,\,(\sin \,\,x)}}{{\sqrt {1 - \,\,{{\sin }^2}\,\,x} }}$ is equal to

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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The value of

\int \frac{{d\,\,(\sin \,\,x)}}{{\sqrt {1 - \,\,{{\sin }^2}\,\,x} }}

is equal to

View answer and explanation

Correct option: A

x + c

Option A (x + c) is correct because the integral simplifies to arcsin(sin(x)) + c, which equals x + c.

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