Question

If $a\,\,{\sin ^2}\,\,x + b\,\,{\cos ^2}\,\,x = c,\,\,\;b\,\,{\sin ^2}\,\,y + a\,\,{\cos ^2}\,\,y = d$ and $a\,\,	an \,\,x = b\,\,	an \,\,y$, then $\frac{{{a^2}}}{{{b^2}}}$ is equal to

Accepted Answer

$\frac{{\left( {a - d} \right)\,\,\left( {c - a} \right)}}{{\left( {b - c} \right)\,\,\left( {d - b} \right)}}$

Answer

$\frac{{\left( {b - c} \right)\,\,\left( {d - b} \right)}}{{\left( {a - d} \right)\,\,\left( {c - a} \right)}}$

Answer

$\frac{{\left( {d - a} \right)\,\,\left( {c - a} \right)}}{{\left( {b - c} \right)\,\,\left( {d - b} \right)}}$

Answer

$\frac{{\left( {b - c} \right)\,\,\left( {b - d} \right)}}{{\left( {a - c} \right)\,\,\left( {a - d} \right)}}$

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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