JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

1 Easy

1 of 1

Analyzing +4 | -1

In which of the following reaction, oxidation number of

{N}

does not change

View answer and explanation

Correct option: C

2 {NO}_2 \rightarrow {N}_2 {O}_4

Option C is correct. In the reaction 2NO2 -> N2O4, the oxidation number of N does not change. It remains +4 on both sides of the equation.

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4