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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
In a function f(x)f(x) is defined for x∈[0,  1],x \in \left[ {0,\;1} \right], then the function f(2  x+3)f\left( {2\;x + 3} \right) is defined for
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Correct option: B
x∈[−3/2,  −1]x \in \left[ { - 3/2,\; - 1} \right]
The correct answer is B (x ∈ [-3/2, -1]) because it is the interval for x that makes 2x + 3 fall within the defined domain [0, 1] of f(x).

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