The range of the function $f\left( x \right) = {x^2} - 6x + 7$ is

$\left( { - \infty ,\;0} \right)$

$\left( { - \infty ,\;\infty } \right)$

$\left( { - \infty ,\; - 2} \right)$

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The range of the function

f\left( x \right) = {x^2} - 6x + 7

View answer and explanation

Correct option: B

\left[ { - 2,\;\infty } \right)

Option B ([ - 2,\;∞ )) is correct because the function can be rewritten as (x-3)² - 2, which has a minimum value of -2 and extends to infinity.

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