NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Hard

1 of 1

Analyzing +4 | -1

Following cell has EMF

0.7995 \mathrm{~V}

\mathrm{Pt}\left|\mathrm{H}_2(1 \mathrm{~atm})\right| \mathrm{HNO}_3(1 \mathrm{M}) \| \mathrm{AgNO}_3(1 \mathrm{M}) \mid \mathrm{Ag}

If we add enough

\mathrm{KCl}

to the

\mathrm{Ag}

cell so that the
final

\mathrm{Cl}^{-}

1 \mathrm{M}

. Now the measured emf of the cell is

0.222 \mathrm{~V}

. The

\mathrm{K}_{s p}

\mathrm{AgCl}

would be-

View answer and explanation

Correct option: A

1 \times 10^{-9.8}

Option A (

1 \times 10^{-9.8}

) is correct because it is calculated using the Nernst equation and the change in EMF to find the concentration of

Ag^+

and then the

K_{sp}

AgCl

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