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JEE PHYSICS MCQ: GRAVITATION

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Given below are two statements:
Statement I: In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E1)\left( {{E_1}} \right) to higher energy orbit (E2),\left( {{E_2}} \right), is given as hf=E1−E2.hf = {E_1} - {E_2}.
Statement II: The jumping of electron from higher energy orbit (E2)\left( {{E_2}} \right) to lower energy orbit (E1)\left( {{E_1}} \right) is associated with frequency of radiation given as f=(E2−E1)h.f = \frac {{\left( {{E_2} - {E_1}} \right)}}{h}.
This condition is Bohr’s frequency condition.
In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Statement I is incorrect but statement II is true
Option D is correct because radiation is emitted when an electron jumps from a higher to a lower energy level, and the frequency is given by f=(E2−E1)hf = \frac{{(E_2 - E_1)}}{{h}}.

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