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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
If cos⁡−1(x/2)+cos⁡−1(y/3)=θ\cos ^{-1}(x / 2)+\cos ^{-1}(y / 3)=\theta, then 9x2−12xycos⁡θ9 x^2-12 x y \cos \theta +4y2+4 y^2 is equal to
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Correct option: C
36sin⁡2θ36 \sin ^2 \theta
Option C, 36sin⁡2θ36 \sin^2 \theta, is correct because by using the cosine addition formula and simplifying, we can derive that 9x2−12xycos⁡θ+4y2=36sin⁡2θ9x^2 - 12xy \cos \theta + 4y^2 = 36 \sin^2 \theta.

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