JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\cot \alpha

equals the integral solution of the inequality

4 x^2-16 x+15<0

and

\sin \beta

equals to the slope of the bisector of the first quadrant, then

\sin (\alpha+\beta) \sin (\alpha-\beta)

is equal to

View answer and explanation

Correct option: B

-4 / 5

Option B (-4/5) is correct because by solving the inequality and using the given information, we can find the values of

\cot \alpha

and

\sin \beta

, and then calculate

\sin(\alpha+\beta)\sin(\alpha-\beta)

using trigonometric identities.

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