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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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In a ΔABC,2a2+4b2+c2=4ab+2ac\Delta ABC,2{a^2} + 4{b^2} + {c^2} = 4ab + 2ac, then cos⁡B\cos B is equal to
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Correct option: D
78\frac{7}{8}
Option D (78\frac{7}{8}) is correct because by rearranging the given equation and using the cosine rule, we can find the value of cos B.

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