To raise the temperature of 1 mole gas from $400 \mathrm{~K}$ to $500 \mathrm{~K}$, how much heat is require while $C_p=3+1.2 \times 10^{-3} \mathrm{~T} \mathrm{~cal} / \mathrm{mol}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Hard

1 of 1

Application +4 | -1

To raise the temperature of 1 mole gas from

400 \mathrm{~K}

500 \mathrm{~K}

, how much heat is require while

C_p=3+1.2 \times 10^{-3} \mathrm{~T} \mathrm{~cal} / \mathrm{mol}

View answer and explanation

Correct option: B

354 \mathrm{~cal}

Option B (354 cal) is correct because it is calculated by integrating the given Cp function over the temperature range.

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{T_i}

{T_f}

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

\Delta G