JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Application +4 | -1

If the tangent to the curve

y = x + \sin y

at a point

\left( {a,b} \right)

is parallel to the line joining

\left( {0,\frac{3}{2}} \right)

and

\left( {\frac{1}{2},2} \right),

then

View answer and explanation

Correct option: A

\left| {b - a} \right| = 1

The correct answer is A (

\left| {b - a} \right| = 1

) because it is found by using the parallel line condition and the curve equation to find the relationship between a and b.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z