JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

\alpha, \beta, \gamma

are the real roots of the equation

x^3-3 a x^2+3 b x-1=0

, then the centroid of the triangle with vertices

\left(\alpha, \frac{1}{\alpha}\right),\left(\beta, \frac{1}{\beta}\right)

and

\left(\gamma, \frac{1}{\gamma}\right)

is at the point

View answer and explanation

Correct option: A

(a, b)

Option A

(a, b)

is correct because the centroid's coordinates are derived directly from Vieta's formulas and the given equation's coefficients.

More Questions from 2D GEOMETRY SYSTEM

Practice All Chapter MCQs →

\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

C(4,4)

P

2 P A=3 P B

A

(0,0)

B

(4,-3)

(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

9 x^2-16 y^2-18 x+32 y-23

=0

25 x^2+9 y^2-50 x-18 y+33=0

(0,0)(3,0)

(0,4)