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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

A body of mass

0.15 \mathrm{~kg}

moving with a velocity of

15 \mathrm{~m}.\mathrm{s}^{-1}

comes to rest when it hits a spring that is fixed at another end. If the force constant of the spring is

1500 \mathrm{~N}.\mathrm{m}^{-1}

, the compression in the spring is

View answer and explanation

Correct option: A

0.15 \mathrm{~m}

Option A (

0.15 \text{{ m}}

) is correct because it is calculated by equating the kinetic energy of the mass to the potential energy stored in the spring.

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