JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In an ambiguous case of solving a triangle when

a = \sqrt 5 ,\;b = 2,\;\angle A = \frac{\pi }{6}

, the two possible values of third side are

{c_1}

and

{c_2}

, then

View answer and explanation

Correct option: C

\left| {{c_1} - {c_2}} \right| = 4

Option C (|c1 - c2| = 4) is correct because it is the difference between the two possible values of the third side, calculated using the cosine rule and solving the quadratic equation.

More Questions from PROPERTIES OF TRIANGLES

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{p_1},{p_2},{p_3}

are altitudes of a

\Delta \;ABC

drawn from the vertices

A,B,C

and

\Delta

the area of the triangle, then

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

is equal to If the sides of the triangles are

5k,\;6k,\;5k

and radius of incircle is 6, the value of

k

is equal to In a

\Delta \,ABC

, if

a = \left( {b - c} \right)\sec \theta

, then

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

is equal to If

\Delta = {a^2} - {\left( {b - c} \right)^2}

, where

\Delta

is the area of

\Delta \;ABC

, then

\tan A

is equal to If

A

is the area and

2 s

is the sum of the sides of a triangle, then