$\int \frac{d x}{(x-\beta) \sqrt{(x-\alpha)(\beta-x)}}$ is

$\frac{2}{\alpha-\beta} \sqrt{(x-\alpha)(\beta-x)}+c$

$\frac{\alpha-\beta}{2}({x}-\alpha) \sqrt{\beta-{x}}$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int \frac{d x}{(x-\beta) \sqrt{(x-\alpha)(\beta-x)}}

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Correct option: A

\frac{2}{\alpha-\beta} \sqrt{\frac{x-\alpha}{\beta-x}}+c

Option B (Only Statement II is true) is correct because the mean is calculated to be 5.16 and the standard deviation is calculated to be 1.54, making only statement II correct.

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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