JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

The value of

\cos (\pi / 13)+\cos (2 \pi / 13)+\ldots .+\cos (12 \pi / 13)

is equal to

View answer and explanation

Correct option: A

Option A (0) is correct because the terms in the cosine series cancel each other out due to the symmetry around

\pi

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\tan \alpha=\frac{p}{q}

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\triangle A B C

C

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\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=